1/9*x^2-x+2=0

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Solution for 1/9*x^2-x+2=0 equation: 


x in (-oo:+oo)

(1/9)*x^2-x+2 = 0

1/9*x^2-x+2 = 0

DELTA = (-1)^2-(1/9*2*4)

DELTA = 1/9

DELTA > 0

x = ((1/9)^(1/2)+1)/(1/9*2) or x = (1-(1/9)^(1/2))/(1/9*2)

x = 6 or x = 3

x in { 3, 6 }

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